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Calculate the standard internal change i...

Calculate the standard internal change in multiples of `-10^(2)KJ` for the reaction `OF_(2(g)) + H_(2)O_((g)) rarr O_(2(g)) + 2HF_((g))` at 298K. The standard enthalpies of formation of `OF_(2(g)), H_(2)O_((g)), HF_((g)) " are " +20, -250 and -270KJ "mole"^(-1)`

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The correct Answer is:
3
`Delta H = Delta H_(f_(O_(2))) + 2 Delta H_(f_(HF)) - Delta H_(f_(OF_(2))) - Delta H_(f_(H_(2)O)`
`= 0 + 2 xx (-270) - (20) - (-250) = -310`
`Delta E = Delta H - Delta ng RT`
`= -310 -1 xx 8.314 xx 0.298 = -312.5`
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