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The enthalpy change when 50 mL of 0.01 M...

The enthalpy change when 50 mL of 0.01 M `Ca(OH)_(2)` reacts with 25 mL of 0.01 M HCl is `5 (x + 2)` can Given that `Delta H^(0)` neutralisation of a strong acid and a strong base in 140 kCal `mol^(-1)`. What is x?

Text Solution

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The correct Answer is:
5
Eq. neutralised `= 25 xx 0.01`
= 0.25 meq. (limiting reagent)
140 kcal `rarr` 1 eq
? `rarr` 0.25 meq
`rArr Delta H = 5 xx 7 rArr 7 = 5 + 2`
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