The efficiency of the reversible cycle d...

The efficiency of the reversible cycle drawn in the fig. will be

0.333

0.56

0.66

0.25

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The correct Answer is:

`eta = (W)/(q_("abs")) = ("area enclosed")/(q_("abs"))`
`= ((1)/(2) xx 100 xx 500)/((1)/(2) xx (500) (250 + 150)) = 0.25` s

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