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1 mole each of CaC(2), Mg(2)C(3) reacts ...

1 mole each of `CaC_(2), Mg_(2)C_(3)` reacts with excess water in separate open flasks work done by the gas during the dissolution shows the order:

A

`CaC_(2) = Mg_(2)C_(3) lt Al_(4)C_(3)`

B

`CaC_(2) = Mg_(2)C_(3) = Al_(4)C_(3)`

C

`Mg_(2)C_(3) lt CaC_(-2) lt Al_(40C_(3)`

D

`Mg_(2)C_(3) lt Al_(4)C_(3) lt CaC_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`CaC_(2) rarr C_(2)H_(2)`
`Mg_(2)C_(3) rarr C_(3)H_(4)`
`Al_(4)C_(3) rarr CH_(4)`
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