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The standard enthalpy of formation of hy...

The standard enthalpy of formation of hypothetical MgCl is `-125kJ mol^(-1)` and for `MgCl_(2)` is -642 kJ `mol^(-1)`. What is the enthalpy of the disproportionation of MgCl ?

A

`-492 kJ mol^(-1)`

B

`-392 kJ mol^(-1)`

C

`-767kJ mol^(-1)`

D

`-517 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

(i) `Mg_((s)) + Cl_(2(g)) rarr MgCl_(2(s)) , Detlta H_(1) = - 642`
(ii) `Mg_((s)) + 1//2Cl_(2(g)) rarr MgCl_((s)) , Delta H_(2) = - 125`
(iii) `2MgCl rarr MgCl_(2) + Mg, Delta H`= ?
`Delta H = Delta H_(1) - Delta H_(2) = - 392 kJ mol^(-1)`
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