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Assuming Delta H^(0) and Delta S^(0) do ...

Assuming `Delta H^(0) and Delta S^(0)` do not change with temperature the boiling point of liquid ''A'' (the thermodynamics data given below) is

A

300K

B

13K

C

150K

D

50K

Text Solution

Verified by Experts

The correct Answer is:
A

`Delta S = 100JK^(-1) mol^(-1), Delta H_("ext") = Delta H_(g) - Delta H_(L)`
`100- (-130) = 30kJ`
`T = (30 xx 1000)/(100) = 300 ( :. T = (Delta H)/(Delta S))`
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