A copper block of mass 2.5 kg is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper `=0.39" Jg"^(-1)K"^(-1),` heat of fusion of water `=335" Jg"^(-1)`).

Explanation

Heat obtained by copper block from furnace,
`Q=m_(1)CDeltatheta` . . . (1)
When heated block is placed on large ice block then `m_(2)` mass of ice starts melting.
Required meat for melting,
`Q.=m_(2)L.` . . .(2)
But `Q=Q.`
`:.m_(1)C Delta theta=m_(2)L.`
`:.m_(2)=(m_(1)C Delta theta)/(L.)`
`=(2.5xx0.31xx500)/(335)`
`=1.455`
`~~1.46`
`~~1.5` kg