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In thermal steady state of rod, temperat...

In thermal steady state of rod, temperature gradient is `5^(@)` C/cm and temperature of its hot end is `100^(@)C`, then at . . . . . . cm distance from hot end its temperature becomes `60^(@)C`.

Text Solution

Verified by Experts

The correct Answer is:
8

`L=(T)/(dT//dx)=(40)/(5)=8cm`
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