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Constant temperature of ends are T(1) an...

Constant temperature of ends are `T_(1)` and `T_(2)` (where `T_(1)gtT_(2)`) for a conducting rod of 'L' length and cross-sectional area A. What would be the rate of heat transfer in thermal steady state ?

A

`(dQ)/(dt)=(KA(T_(1)-T_(2)))/(L)`

B

`(dQ)/(dt)=KAL(T_(1)-T_(2))`

C

`(dQ)/(dt)=(KA(T_(1)-T_(2)))/(2)`

D

`(dQ)/(dt)=(KL(T_(1)-T_(2)))/(A)`

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The correct Answer is:
C

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