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A particle executing simple harmonic mot...

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of `31.4 cm"/"s`. The frequency of its oscillation is……….

A

4 Hz

B

3 Hz

C

2 Hz

D

1 Hz

Text Solution

Verified by Experts

The correct Answer is:
D
From maximum velocity in SHM,
`v_("max")= A omega = A(2pi f)`
`therefore f= (v_("max"))/(2pi A)`
`=(31.4)/(2(3.14)(5))= 1Hz`.
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