The displacement of a SHM particle is `y= 3 sin omega t+4 cos omega t` then its amplitude will be……

Options

A. `7`
B. `1`
C. `5`
D. `12`

Answer

C

Explanation

Comparing given equation
`y= A sin omega t+ B cos omega t` with equation
`y= 3sin omega t+4 cos omega t`
`A= 3" and "B= 4`
amplitude `a= sqrt(A^(2)+B^(2))`
`= sqrt((3)^(2)+(4)^(2))`
`therefore a= 5`.