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A man walking briskly in rain with speed...

A man walking briskly in rain with speed v must slant his umbrella forward making an angle `theta` with the vertical. A student derives the following relation between `theta` and v: `tan theta` = v and checks that the relation has a correct limit : as `vtoo, thetato0`, as expected , (we are assuming there is no strong wind and that the rain falls vertically for a stationary man.) Do you think this relation can be correct ? If you, guess the correct relation.

Text Solution

Verified by Experts

Relation obtained by student, `tantheta=v`
Dimensions of left hand side of equation `M^(0)L^(0)T^(0)` because it.s a trignometric ratio.
and dimensions of right side are `M^(0)L^(1)T^(-1)` Hence, given relation is not true.
True relation should be `tantheta=(v)/(u)`. where u= initial speed or velocity.
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Knowledge Check

  • The relation between B_(h), B_(v) and B is ……..

    A
    `B= sqrt(B_(h)^(2)+B_(v)^(2))`
    B
    `B= B_(h).B_(v)`
    C
    `B= (B_(v))/(B_(h))`
    D
    `B= (B_(h))/(B_(v))`
  • The relation between B_(v) , B_(h) and B is ….... .

    A
    `B= sqrt(B_(h)^(2) + B_(v)^(2))`
    B
    `B= B_(h). B_(v)`
    C
    `B= (B_v)/( B_h)`
    D
    `B= (B_h)/(B_v)`
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