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Measure of two quantities along with the...

Measure of two quantities along with the precision of respective measuring instrument is `A = 2.5 ms^(-1) + 0.5 ms^(-1) B = 0.10 s +- 0.01 s` . The value of AB will be

A

`(0.25+-0.08)m`

B

`(0.25+-0.5)m`

C

`(0.25+-0.05)`

D

`(0.25+-0.135)`

Text Solution

Verified by Experts

Given
`A=(2.5+-0.5) ms^(-1), B=(0.10s+-0.01)`s
`x=AB=(2.5)(0.10)=0.25 m`
`(Deltax)/(x)=(DeltaA)/(A)+(DeltaB)/(B)`
`=(0.5)/(2.5)+(0.01)/(0.10)=(0.05+0.025)/(0.25)(0.075)/(0.25)`
`Deltax=0.075=0.08` m (By rounding off to two significant figures)
`AB=(0.25+-0.08)m`
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