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A heavenly body is observed from two dia...

A heavenly body is observed from two diametrically opposite points A and B on the earth. The angle substended at the heavenly body is `2.9 xx 10^(-4)` rad. Given the diameter of Earth to be about `1.28 xx 10^(7)` Compute the distance of the heavenly body from the earth.

A

`2.267xx10^(-11) m`

B

`4.413xx10^(7)m`

C

`4.413xx10^(10)`

D

`4.413xx10^(10)m`

Text Solution

Verified by Experts

`D=(b)/(theta)=(1.28xx10^(7)m)/(2.9xx10^(-4)rad)=4.413xx10^(10)m`
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