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When a current of (5 +- 0.5)A flows thro...

When a current of `(5 +- 0.5)A` flows through a wire, it develops a potential difference of `(40 +- 1)V`. The resistance of the wire is ......

A

`(8+-1.5) Omega`

B

`(8+-0.5)Omega`

C

`(8+-1)Omega`

D

`(8+-2)Omega`

Text Solution

Verified by Experts

`R=(V)/(1)=(40)/(5)=8Omega`
`:.(DeltaR)/(R)=(DeltaV)/(V)+(DeltaI)/(I)`
`:. (DeltaR)/(8)=(1)/(40)+(0.5)/(5)=(1+4)/(40)=(5)/(40)`
`:. DeltaR=(5)/(40)xx8=1Omega`
`:.` Resistance of wire `=R+-DeltaR`
`=(8+-1)Omega`
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