Let `|epsi_(0)|` denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then

Options

A. `[epsi_(0)]=[M^(-1)L^(-3)T^(2)A]`
B. `[epsi_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`
C. `[epsi_(0)]=[M^(-1)L^(2)T^(-1)A^(-2)]`
D. `[epsi_(0)]=[M^(-1)L^(2)T^(-1)A]`

Explanation

`F=(q_(1)q_(2))/(4pi epsi_(0)^(r)) rArr epsi_(0)=(q_(1)q_(2))/(4pi Fr^(2))`
`:.[epsi_(0)]=([q_(1)][q_(2)])/([F][r^(2)]) " " [ :. 4pi` is dimensionless]
`=((AT)(AT))/((M^(1)L^(1)T^(-2))(L^(2)))`
`=M^(-1)L^(-3)T^(-4)A^(2)`