The current voltage relation of diode is given by `I = (e^(1000V//T) - 1)` mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring `+-0.01` V while measuring the current of 5mA at 300K, what will be the error in the value of current in.

Options

A. `0.5 mA`
B. `0.05 mA`
C. `0.2 mA`
D. `0.02 mA`

Explanation

`I=(e^(1000V//T)-1)mA....(1)`
`:.5mA=e^(1000V//T)mA-1mA`
`:.6mA=e^(-1000V//T)mA`
`:.dt=e^(1000V//T)mAxx(1000)/(T)dv`
`=6mAxx(1000)/(300)xx0.01`
`=6xx(10)/(300)`
`=0.2 mA`