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A student measures the time period of 10...

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is Is, then the reported mean time should be :

A

`92+-3 s`

B

`92+-2s`

C

`92+-2s`

D

`92+-1.8s`

Text Solution

Verified by Experts

True value `=(90+91+95+92)/(4)=92`
Mean absolute error `=(2+1+3+0)/(4)=(6)/(4)=1.5`
Value `(92+-1.5)`
Since `L.C=1s`
`:.` Value `92+-2s`
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KUMAR PRAKASHAN-UNITS AND MEASUREMENT-SECTION -E (MULTIPLE CHOICE QUESTIONS (MCQS) (MCQS ASKED IN GUJARAT BOARD AND COMPETITIVE EXAMS)
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  11. Write dimension of permeability of vacuum.

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