Dimension of a physical quantity is `M^(a)L^(b)T^(c)`, then it is ......

Options

A. velocity if `a=1,b=0,c=-1`
B. accceleration if `a=1,b=1,c=-2`
C. force if `a=0,b=-1,c=-2`
D. pressure if `a=1,b=-1,c=-2`

Explanation

`(A) M^(1)L^(0)T^(-1)`
which is not dimension of velocity.
(B) `M^(1)L^(1)T^(-2)`
which is dimension of force but not acceleration.
(c) `M^(0)L^(-1)T^(-2)`
Which is not dimension of force.
(D) `M^(1)L^(-1)T^(-2)`
which not dimension of pressure.