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Dimension of [mu(0)epsi(0)]^(-(1)/(2)).....

Dimension of `[mu_(0)epsi_(0)]^(-(1)/(2))`....

A

`L^((1)/(2))T^(-(1)/(2))`

B

`L^(-1)T`

C

`L^(1)T^(-1)`

D

`L^(-(1)/(2))T^((1)/(2))`

Text Solution

Verified by Experts

`[mu_(0)epsi_(0)]^((-1)/(2))=(1)/(sqrt(mu_(0)epsi_(0)))=` velocity
`:. [mu_(0)epsi_(0)]^(-(1)/(2))=[v]`
`=M^(0)L^(1)T^(-1)`
`=LT^(-1)`
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