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To measure gravitational acceleration by...

To measure gravitational acceleration by using simple pendulum, length of pendulum `(0.8pm0.01)` m and periodic time `(2.5pm0.12)` s. Find percentage error in measurement of g.

A

10.85

B

12.75

C

15.85

D

21.12

Text Solution

Verified by Experts

The correct Answer is:
A
`T=2pisqrt((l)/(g))`
`:.T^(2)=(4pi^(2)l)/(g)`
`:.g=(4pi^(2)l)/(T^(2))`
`[:.4pi^(2)` = constant]
`:.` % error in measurement of g,
`(Deltag)/(g)xx100%=(Deltal)/(l)xx100%+2(DeltaT)/(T)xx100%`
`=(0.01)/(0.8)xx100%+2xx(0.12xx100)/(2.5)`
`=1.25%+9.6%`
`=10.85%`
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