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A bullet of mass 0.04 kg moving with a s...

A bullet of mass 0.04 kg moving with a speed of `90 m s^(-1)` enters a heavy wooden block and is stopped after a distance of 60 cm. What is the average resistive force exerted by the block on the bullet?

Text Solution

Verified by Experts

let constant retardatin of bullel is a
We know that a=` (mu^(2))/( 2s )`
`=- 6750 ms^(-2)`
From Newtons second law of motion
`F= ma `
`= 0.04 xx 6750`
Actually this is retarding force retardatin will not be constant .so answer will show average force
W= `Delta k , m= 0.04 kg v_(1) = 90 m//s`
`:. F.d = (1)/(2) m (v_(2)^(2) - v_(1)^(2))`
`:. F= (mxx 4050)/( d ) `
`:. F- 270 N`
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