A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 `ms^(-2)`, what would be the reading of the weighing scale ? (g = 10 `ms^(-2)`)

Explanation

m= 15 kg , g =10 `m/s^(2)`
acceleration of lift = 9`m//s^(2)`

When lift descend (moves in downward direction with acceleration of `9m//s^(2))`
`=10 - 9 = 1 m//s^(2)`
Apparent weight of person
`R= mg `
`=50 xx 1`
`=50 N`
Reading of weighing scale
`(R )/( g ) = (50)/( 10) = 5 kg`