A water jet sprinkle water around it. If speed of water is v, then maximum area covered by water jet will b e .......

Options

A. `(piv^(2))/(g^(4))`
B. `(piv^(2))/(2g^(2))`
C. `(piv^(4))/(g^(2))`
D. `(piv^(2))/(g)`

Answer

C

Explanation

motion of water coming out will be projectile motion
Maximum range of projectile will be
`R_(max) = (v^(2))/( G ) `
Area covered = `piR^(2)`
`= pi ((v^(2))/(g ))^(2)`
`(piv^(2))/( g^(2))`