A ring of radius R and linear charge density `lambda` on its surface is performing rotational motion about an axis perpendicular to its plane. lf the angular velocity of the ring is `omega`, how much current is constituted by the ring?

Options

A. R`omega lambda`
B. `R^(2) omega lambda`
C. `R omega^(2) lambda`
D. `R omega lambda^(2)`

Answer

A

Explanation

`R omega lambda`
Linear charge density of electric charge collected on ring = `lambda`
`therefore ` Total charge on ring (Q) = `lambda L = lambda (2 pi R)`
As ring rotates at the angular speed ro, let electric current due to it = I.
` I = (Q)/(l) = (Q)/(T) = (2 pi R lambda)/(T) = (2 pi R lambda)/((2 pi )/(omega)) " " (because omega = (2pi)/(T))`
I = R `omega lambda `