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Charge passing through the cross-section of a conductor h given by Q = B' + A' `t^(2)` . What will be the current in ampere at lime t = 10 s ?

A

5 A'

B

10 A'

C

20 A'

D

40 A'

Text Solution

Verified by Experts

The correct Answer is:
C
20 A.
I = `(dQ)/(dt ) = (d)/(dt) (B. + A. t^(2)) `
`therefore I = 0 + 2A. t `
`therefore I = 2A. xx 10 = 20 A.`
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