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On applying an electric field of 15 xx ...

On applying an electric field of `15 xx 10^(-6) vm^(-1) ` across a conductor , current density through it is 3.0 `Am^(-2)`. The resistivity of the conductor is .......

A

`45 xx 10^(-6) Omega m`

B

`5 xx 10^(-6) Omega `m

C

`0.5 xx 10^(-6) Omega m `

D

`2 xx 10^(5) Omega` m

Text Solution

Verified by Experts

The correct Answer is:
B
`5 xx 10^(-6) Omega `m
`J = sigma E rArr (E)/(rho)`
`therefore rho = (E)/(J) = (15 xx 10^(-6))/(3) = 5 xx 10^(-6) Omega`m
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KUMAR PRAKASHAN-CURRENT ELECTRICITY-SECTION [D] MULTIPLE CHOICE QUESTIONS (MCQs) (MCQs FROM .DARPAN. BASED ON TEXTBOOK)
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  14. Resistance or coil at 100^(@)C is 4.2 Omega. If temperature co-efficie...

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  15. Resistance of a wire is ROmega. It is stretched uniformly till Its len...

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  16. Resistivity of ideal conductor and ideal insulator are rho(1) and rho...

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