When 10 resistors, each with resistance `(1)/(10) Omega` are connected in parallel , equivalent resistance will be ......

Options

A. `1 Omega`
B. `100 Omega `
C. `(1)/(100) Omega`
D. `10 Omega`

Answer

C

Explanation

`(1)/(100) Omega`
`(1)/(R_(p)) = (1)/((1)/(10)) + (1)/((1)/(10)) + (1)/((1)/(10)) + .... + 10 ` times
` = (10)/((1)/(10)) `
`(1)/(R_(p)) = (100)/(1) " " therefore R_(p) = (1)/(100) Omega`