A wire has resistance of `24 Omega` is bent in the following shape. The effective resistance between A and B is

Options

A. `24 Omega`
B. `10 Omega`
C. `(16)/(3) Omega`
D. None of these

Answer

B

Explanation

`10 Omega`
Total length of wire = 5 + 5 + 5 + 5 = 20 cm
So resistance for unit length `lambda = (24)/(20) = 1.2 Omega` /cm So resistance of wire of 5 cm. = `1.2 xx 5 = 6 Omega` New equivalent resistance of equilateral triangle
`= (12 xx 6)/(12 + 6) = (72)/(18) = 4 Omega`
` therefore ` Resistance between P and Q = 4 + 6 = ` 10 Omega`