Internal resistance of cell having emf 24 V is `0.12 Omega`. If cell is joined with external resistance 3 `Omega`, so terminal voltage of cell is .......

Options

A. 23.08 V
B. 2V
C. 0.1 V
D. 3.8 V

Answer

A

Explanation

23.08 V
In `epsilon = V + Ir`
I = `(epsilon)/(R + r) = (24)/(3.0 + 0.12) = (24)/(3.12) = 7.6 `A
V = `epsilon - Ir`
=` 24 - 7.6 xx .12`
= 24 - 0.912
23.08 V