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A 10 Omega resistance is connected with...

A `10 Omega` resistance is connected with an electric cell. Now this resistance is replaced by a `20 Omega` resistance. The potential difference between two poles of the cell

A

will increase

B

will decrease

C

will remain the same

D

will get discharged immediately

Text Solution

Verified by Experts

The correct Answer is:
A
will increase
`epsilon` and r are constant in V = `epsilon` - Ir, but connecting 20`Omega` instead of 10`Omega` cannot flowing through the circuit decreses
So as per equation V= `epsilon - Ir,` V increases.
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KUMAR PRAKASHAN-CURRENT ELECTRICITY-SECTION [D] MULTIPLE CHOICE QUESTIONS (MCQs) (MCQs FROM .DARPAN. BASED ON TEXTBOOK)
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  11. n identical bulbs operating on same voltage are available. When all su...

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  12. Maximum power in a 0.5Omega resistance connected with two batteries of...

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  13. An electric bulb marked 40 W and 200 V is used in a circuit of supply ...

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  17. n identical cells each of emf epsilon and lnternal resistance r are co...

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  19. The resistance of a 10 m long potentiometer wire is 20 Omega . It is c...

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  20. A potentiometer wire is 100 cm long and a constant potential differenc...

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