n identical bulbs operating on same voltage are available. When all such bulbs are connected in series to the same operating voltage source, then power consumed in each bulb = ...... W.

Options

A. nP
B. P
C. `(P)/(n)`
D. `(P)/(n^(2))`

Answer

C

Explanation

`(P)/(n)`
The resistance of every bulb R = `(V^(2))/(P)`
The total resistance joined in series of n bulb
R. = nR = `(nV^(2))/(P)`
`therefore `Total Power P. = `(V^(2))/(R.) = (V^(2) xx P)/(nV^(2)) = (P)/(n)`