n resistors each of resistance r are connected to a battery of emf `epsilon` and internal resistance r. Then the ratio of terminal voltage to emf of battery = ...... .

Options

A. n
B. `(n)/(n + 1)`
C. `(1)/(n+ 1)`
D. `(n+ 1)/(n)`

Answer

B

Explanation

`(n)/(n+ 1) `
`epsilon = I xx ` total resistance of circuit

`epsilon = I xx (n + 1) r " " `...... (1) and
V = I (r + r + r + ... N times)
V = Inr ...... (2)
`therefore (V)/(epsilon) = (n)/(n+ 1)`