Seven resistance each of 20`Omega` are connected with 2 volt battery, reading of ammeter will be.

(a) `((1)/(10))`A
(b) `((3)/(10))` A
(c) `((4)/(10)) `A
(d) `((7)/(10)) `A

Options

A. `((1)/(10))`A
B. `((3)/(10))` A
C. `((4)/(10)) `A
D. `((7)/(10)) `A

Answer

C

Explanation

`((4)/(10)) `A
All resistance are in parallel. so p.d. of all resistance is same.
`therefore V = IR `
`therefore 2 =I xx 20 `
`therefore I = (I)/(10)`
Ammeter is connected after 4 resistance, so its reading become = `(4)/(10)` A