A carbon resistor of `(47 pm 4.7) k Omega` is to be marked with rings of different colours for its marked with rings of different colours for its identification. The colour code sequence will be

Options

A. Green - Orange - Violet - Gold
B. Violet - Yellow - Orange - Silver
C. Yellow - Green - Violet - Gold
D. Yellow - Violet - Orange - Silver

Answer

D

Explanation

Yellow - Violet - Orange - Silver
R = `(47 pm 4.7) xx 10^(3) Omega`
= `(47 xx 10^(3) pm 4700) Omega and (4700 xx 100)/(47000) = 10%`
`= (47 xx 10^(3) pm 10% ) Omega`
From colour code, `4 rarr` yellow, 7 `rarr` violet , 3 `rarr` orange, 10 % for gold.