Why maximum kinetic energy of photoelectron cannot be negative?

The photoelectric cut-off voltage in a certain experiment is 1.5 v. What is the maximum kinetic energy of photoelectrons emitted?

The photoelectric cutoff voltage in a certain expertiment is 1.5 V.What is the maximum kinetic energy of photoelectrons emitted?

Let K_(1) be the maximum kinetic energy of photoelectrons emitted by a light of wavelength lambda_(1) and K_(2) corresponding to lambda_( 2). If lambda_(1) = 2lambda_(2) , then

Define kinetic energy

When an electro-magnetic radiation is incident on the surface of metal, maximum kinetic energy of photoelectron depends on-

Statement-1 : Light described at a place by the equation E= E_(0) (sin omegat + sin 7 omegat) falls on a metal surface having work funcation phi_(0) . The macimum kinetic energy of the photoelectrons is KE_(max) = (7homega)/(2pi) - phi_(0) Statement-2 : Maximum kinetic energy of photoelectron depends on the maximum frequency present in the incident light according to Einstein's photoelectric effect equation.

The kinetic energy of the object

When photon of v frequency os incident on photo sensitive surface with V_(0) threshold frequency,maximum kinetic energy of photo-electron emitted will be….

How maximum kinetic energy of photoelectron depend on frequency ?it do not depend on which factors?