Find the
(a)Maximm frequency,and
(b)Minimum wavelength of X-rays produced by 30 kV electrons.

Explanation

Here V=30 KV=`3xx10^(4)` V,h=`6.63xx10^(-34)` Js
(a) [maximum K.E of photon of X-ray]=[Maximum K.E. of electron accelerated with volt V]
`therefore hv_(max)=eV`
`therefore v_(max)=(eV)/(h)`
`=(1.6xx10^(-19)xx3xx10^(4))/(6.63xx10^(-34))`
`0.72398xx10^(19)Hz`
`therefore v_(max)7.24xx10^(18)Hz`
(b) Now,
`C=V_(max)xxlambda_(min)`
`therefore lambda_(min)=(c)/(v_(max))`
`=(3xx10^(8))/(7.24xx10^(18))`
`=0.41436xx10^(-10)m=0.0414` nm