Calculate the
(a)Momentum ,and
(b)de-Broglie wavelength of the electrons accelerated through a potential differene of 56 V.

Explanation

V=56 V
Kinetic energy of electron ,
`K=Vxxe` (a)Momentum of electron,
`p=sqrt(2mK)`
`=sqrt(2xx9.1xx10^(-31)xx56xx1.6xx10^(-19))`
`=sqrt(1630.72xx10^(-50))`
`=40.38xx10^(-25)`
`~~4.04xx10^(-24)kg ms^(-1)`
(b)de-Broglie wavelength,
`lambda=(h)/(p)=(6.63xx10^(-34))/(4.04xx10^(24))`
`=1.64xx10^(-10)m`
1.64 Å