For the circuit shown in the figure, calculate the equivalent resistance for the two cases given as : (1) `V_(A) gt V_(B) and (2) V_(B) gt V_(A)`. Here consider `D_(1) and D_(2)` to be ideal diodes.

Options

A. `50, oo`
B. 25, 25
C. `oo, 25`
D. `25, oo`

Answer

D

Explanation

`25, oo`
(i) When `V_(A) gt V_(B)`, then `D_(1) and D_(2)` will be formed biased and hence their resistance will be zero and the circuit will be as following.

`therefore ` Equivalent resistance `=(50xx50)/(50+50)=25Omega`
(ii) When `V_(B) gt V_(A)`, then `D_(1) and D_(2)` will be reverse biased and hence their resistance will be `oo` and the circuit will be as following.

`therefore` Equivalent resistance will be `(oo)`.