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Calculate magnetic moment of Fe^(+3) ion...

Calculate magnetic moment of `Fe^(+3)` ions. (Fe= 26)

A

5.9BM

B

0.59BM

C

59 BM

D

590BM

Text Solution

Verified by Experts

The correct Answer is:
A
Electronic configuration of `Fe^(+3) = [Ar] 3d^(5) 4s^(0)` So, d-orbital
here, 5 unpaired electrons are present in d-orbitals so, magnetic momentum `mu = sqrt(n(n+2))`
`=sqrt(5(5+2))= 5.9BM`
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KUMAR PRAKASHAN-THE D-AND F-BLOCK ELMENTS-Section -E (Multiple Choice Question (MCQs))
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