Calculate spin magnetic momentum of `M_((aq))^(+2)` ions. (Z=27)

Options

A. 3.80BM
B. 3.87BM
C. 0.387BM
D. 38.7BM

Answer

B

Explanation

Here, atomic number Z=27
So, for M ions `=[Ar] 3d^(7) 4s^(2)`
So, for `M^(+2)` ions = `[Ar] 3d^(7)`

Here, unpaired electrons are 3.
`:.` Magnetic momentum `mu = sqrt(n(n+2)) = sqrt(3(3+2)) = 3.87BM`