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pH of a mixture of HA and A^(-) buffer ...

pH of a mixture of HA and `A^(-) ` buffer is 5. `K_b of A^(-) =10 ^(-10 ) .Hence [HA]/ [A^(-) ]` will be

A

1

B

10

C

`0.1`

D

`100`

Text Solution

Verified by Experts

The correct Answer is:
C
`pH =5 = pKa +log ""([S])/([A]) `
` pKa +pKb =14 rArr pKa =1 4 -10 =4`
` 5=4 +log ""([S])/([A]) rArr ([A^(-)])/([H_A]) =10`
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