How many grams of NaOH can neutralise 100 ml of ` H_2SO_4 ` solution with `P^(H) ` solution with `P^(H) ` value 3.301?

Options

A. 2mg
B. 3 mg
C. 4 mg
D. 0.4 mg

Answer

A

Explanation

` pH = 3.3 rArr [H^(+) ] = 5xx 10 ^(-4) `
` therefore ` moles of acid ` = 0.1 xx 5 xx 10 ^(-4) = 5 xx 10 ^(-5) `
to neutralize , moles of NaOH `= 5 xx 10 ^(-5) `
` therefore ` weight ` = 40 xx 5 xx 10 ^(-5) = 2 xx 10 ^(-3) = 2 mg `