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What is the concentration of CN^(-) ion...

What is the concentration of `CN^(-) ` ions in a solution with 0.1 M HCl and 0.01 M HCN where `K_a` of HCN is `10 ^(-6) ` ?

A

`10 ^(-4) M `

B

`10 ^(-5)M`

C

` 10^(-6) M`

D

` 10 ^(-7)M`

Text Solution

Verified by Experts

The correct Answer is:
D
` [H^(+) ] = 10 ^(-1) ` (only from HCl)
` K_a = 10 ^(-6) =([H^(+) ][CN^(-) ])/([HCN]) =( [10 ^(-1) ]xx [CN^(-)]) /( 10^(-2)) `
`rArr [CN^(-) ]= 10 ^(-7) `
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