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If the equlibrium constant for the react...

If the equlibrium constant for the reaction of weak acid HA with strong base is `10^(9)` then calculate the pH of 0.1 M NaA.

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The correct Answer is:
9
`K_n =10 ^(9) , K_h =(1)/( K_n) = 10 ^(9) `
` K_a =(K_W)/( K_h) = 10 ^(-5) rArr pH =7 + (P^(K_a))/( 2) + (1)/(2) log C `
` =7 + (5)/(2) +(1)/(2) log 10 ^(-1) = 9`
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