The molar solubility of `Pbl_(2) in 0.2M Pb(NO_(3))_(2)` solution in terms of solubility product, `K_(sp)`

Options

A. `(K_(sp)//0.2) ^(1//2)`
B. ` (K_(sp)//0.4) ^(1//2)`
C. ` (K_(sp)//0.8 )^(1//2)`
D. ` (K_(sp)//0.8 )^(1//3)`

Answer

C

Explanation

` PbI_2 hArr Pb^(+2) +2I^(-) `
` Pbunderset( 0.2 M) ((NO_3) ) _2 to Punderset( 0.2M) b^(+2) + 2NO_3^(-) `
` K_(sp) =(S+0.2) (2S)^(2) rArr S= (K_(sp)//0.8)^(1//2) `