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What is the pH of a solution obtained by...

What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, `Ca(OH)_(2)` , to form 100 ml of a saturated solution (aqueous)? `(K_(w)=1.0xx10^(-14) "mole"^(2) "litre"^(-2))`

A

`9.8`

B

` 11.7`

C

` 12.0 `

D

` 3.0 `

Text Solution

Verified by Experts

The correct Answer is:
C
` M= ( 5 xx 10 ^(-4) )/(100) xx 1000 = 5 xx 10 ^(-3) `
` therefore N= M xx n = 0.01 M`
` [OH^(-)] =10 ^(-2) N rArr pOH =2 rArr pH =12`
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