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H3PO4 +H2O hArr H3O^(+) +H2PO4^(-) ,pK1 ...

`H_3PO_4 +H_2O hArr H_3O^(+) +H_2PO_4^(-) ,pK_1 =2.15 ,`
`H_2PO_4^(-) +H_2O hArr H_3O^(+) HPO_4^(-2) , pK_2 =7.20 ` Hence pH of 0.01 M `NaH_2PO_4` is

A

` 9.35`

B

` 4. 675`

C

` 2. 675`

D

` 7.350`

Text Solution

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The correct Answer is:
B

` NaH_2PO_4` - amphoteric salt
` pH= (p^(Ka_1) +p^(Ka_2))/( 2) = (2.15 +7.20)/( 2) = 4.675`
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AAKASH SERIES-IONIC EQUILIBRIUM -ADDITIONAL PRACTICE EXERCISE (LEVEL -I (MAIN) (Straight Objective Type Questions))
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  18. Solubility of Hg2Cl2 in a solvent is S moles/ litre.Its solubility pro...

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