An organic compound on analysis was found to contain `16.27%` carbon. `0.67%` Hydrogen, `72.2%` chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound. 

Explanation

Empirical formula of the compound `=C_(2)HCl_(3)O`
`(2xx 12)+(1 xx 1)+(3 xx 35.5) +(1 xx 16)=147.5`
Molecular weight `=2x V.D. =2 xx 73.75=147.50`
`n=("Molecular weight")/("Empirical formula weight")=(147.50)/(147.50)=1`
Molecular formula `=C_(2)HCl_(3)O`