The empirical formula an organic substance is `CH_(2)O`. If `3 xx 10^(22)` molecules of the substance has a mass of one sixth of mass of one gram mole of water, find the hybridisation of carbon atoms in the compound. 

Explanation

One mole water =18g
`3 xx 10^(22)` molecules of compound =3g
`6 xx 10^(23)` molecules of compound=?
Molar mass of compoundis `(6 xx 10^(23))/(3 xx 10^(22)) xx 3=60g" "n=(60)/(30)=2`
Molecular formula is `C_(2)H_(4)O_(2)=CH_(3)-overset(O)overset(||)(C)-OH`
Hybridisation of .C. atoms is `sp^(2), sp^(3)`.